H2O2 → 2H+ + O2 + 2e– ; E0 = – 0.68V. The above equation represents which of the following behaviour of H2O2?

: E° = -0.68V.→ In the above equation H2O2 itself undergoes oxidation. Therefore in the above equation H2O2 acts (or) behaves as reducing agent (reductant)Note :- The substances which reduces the another substance and itself undergoes oxidation is said to be reducing agent.i.e., An agent which brings the reduction in another substance is called reductant.