H2O2 → 2H+ + O2 + 2e– ; E0 = – 0.68V. The above equation represents which of the following behaviour of H2O2?
: E° = -0.68V.
→ In the above equation H2O2 itself undergoes oxidation. Therefore in the above equation H2O2 acts (or) behaves as reducing agent (reductant)
Note :- The substances which reduces the another substance and itself undergoes oxidation is said to be reducing agent.
i.e., An agent which brings the reduction in another substance is called reductant.