Questions
H2O2 → 2H+ + O2 + 2e– ; E0 = – 0.68V. The above equation represents which of the following behaviour of H2O2?
detailed solution
Correct option is B
: E° = -0.68V.→ In the above equation H2O2 itself undergoes oxidation. Therefore in the above equation H2O2 acts (or) behaves as reducing agent (reductant)Note :- The substances which reduces the another substance and itself undergoes oxidation is said to be reducing agent.i.e., An agent which brings the reduction in another substance is called reductant.Similar Questions
In the reaction, H2S + H2O2 → S + 2H2O
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