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Q.

H2O2, is '5.6 volume', then

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a

It is 1.7% weight by volume

b

it is 1 N

c

Both (a) and (b)

d

None of the above

answer is C.

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Detailed Solution

Volume Strength of H2​O2​=Normality×5.6Given,  Volume strength =5.6Hence, Normality =5.6/5.6​=1NFor 100 Vol =30% (w/w) H2​O2​Hence 5.6 Vol =0.3×5.6=1.7% weight by volume
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