First slide

Conductivity , Molar conductivity and Equivalent Conductivity

Question

HA is a weak electrolyte. At 25⁰C, the degree of dissociation of 0.5 mol L^–1 HA is 0.1. What is its molar conductivity (in S cm² mol^–1) ? (The limiting molar conductivity of HA is,390 S cm² mol^–1)

Easy

Solution

For mono basic acid λ_M = λ_N
For weak electrolyte
$\alpha = \frac{{{\lambda _M}}}{{{\lambda _\infty }}}$

${\lambda _M} = \alpha {\lambda _\infty } = 0.1 \times 390 = 39$

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