The half cell reactions for the corrosion are,2H++12O2+2e-→H2O; E0 = 1.23VFe2++2e-→Fe(s); E0 = – 0.44V.Find the ΔG0(in kJ) for the overall reaction

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–76

–322

–161

–152

answer is B.

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Detailed Solution

During corrosion higher SRP is cathode and lower SRP is anode.

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