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Q.

The half life of C-14 is 5600 years. A sample of freshly cut wood from a tree contains 10 mg of C-14. The amount left in the sample after 50000 years is (a - x) × 100. The value of (a-x) × 100 is

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answer is 2.

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Detailed Solution

t=2.303Klog⁡aa−xK=0.693t1/2=0.6935600or log⁡aa−x=50000×0.6935600×2.303or log⁡10a−x=50000×0.6935600×2.303or (a - x)=0.02 mg    ∴(a-r) × 100=0.02×x 100-2mg
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