Half life of a radioactive substance A is two times the half life of another radioactive substance B. Initially, the number of nuclei of A and B are No and N, respectively. After three half lives of A, number of nuclei of both become equal. The ratio of NA/NB will be
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a
1/2
b
1/8
c
1/3
d
1/6
answer is B.
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Detailed Solution
We know that the amount remaining after n half lives can be calculated asN=N012nRemaining amount of A = NA123Remaining amount of B = NB126NA123=NB126NANB=864=18