The half life for the reaction N2O5⇌2NO2+12O2 is, 24 hrs at 30° C . Starting with 10 g of N2O5 how many grams N2O5 of will remain after a period of 96 hours
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answer is 0.62.
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Detailed Solution
k=0.69324hr−1=2.30396log10a−x or log10a−x=1.2036 or 1−log(a−x)=1.2036 or log(a−x)=−0.2036=1.7964 or (a−x)= antilog 1.7964=0.6258gm.