Half litre each of three samples of H2O2 labelled 10 vol., 15 vol., 20 vol. are mixed and then diluted with 1700 mL of water. Calculate approximate volume strength of resultant H2O2 solution.
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answer is 7.
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Detailed Solution
Volume strength of H2O2=5.6×N∴ 10 vol. H2O2=105.6N H2O215 vol. H2O2=155.6N H2O220 vol. H2O2=205.6N H2O2Let 500 mL of each is mixed then total volume of mixture = 1500 mL.Also this diluted with 1700 mL. So total volume becomes 3200 mL.N×3200=10×5005.6+15×5005.6+20×5005.6or NH2O2 mixture =500×455.6×3200=1.255∴ Vol. strength of I2O2=1.255×5.6=7.03≈7