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Q.

The half-cell reduction potential of a hydrogen electrode at pH = 10 will be

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a

0.59 V

b

-0.59 V

c

0.059 V

d

-0.059 V

answer is B.

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Detailed Solution

Ered=Ecello+0.0591nlog⁡[H+]       =0+0.05911log⁡[10−10]       =+0.0591×−10=−0.59 V
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The half-cell reduction potential of a hydrogen electrode at pH = 10 will be