First slide

Kinetics of nuclear reactions or nuclear chemistry

Question

The half-life of $_{11}^{24} Na$ is 15 hours. What percentage of it remains after 60 hours ?

Moderate

A

0.00%
B

3.13%
C

6.25%
D

12.5%

Solution

$N = N_{0} {(\frac{1}{2})}^{n} n = \frac{total time}{T_{50}} = \frac{60}{15} = 4$
$N = 100 {(\frac{1}{2})}^{4} = 6 .25 %$

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