The half-life for the reaction N2O5⇌2NO2+12O2 is 24 hr at 30oC. Starting with 10 g of N2O5 how many grams of N2O5 will remain after a period of 96 hours?
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a
1.25 g
b
0.63 g
c
1.7 g
d
0.5 g
answer is B.
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Detailed Solution
k=0.69324hr−1=2.30396log10a−x log10a−x=1.2036 1−log(a−x)=1.2036 log(a−x)=−0.2036 (a−x)=antilog -0.2036=0.6258 g