The H-Cl bond length is 1.275 Ao (charge e - 4.8 × 10-10 esu). lf μ = 1.02 D, then HCI is

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100% ionic

83% covalent

50% covalent

40% ionic

answer is B.

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Detailed Solution

The percent ionic nature= Observed μ Theoretical μ×100=1.021.275×4.8×100= l7 % ionic or = 83% covalent.

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