Heat capacity of water is 18 cal-degree-1-mol-1. The quantity of heat needed to rise temperature of 18g water by 0.2oC is X cal. Then amount of CH4(g) to be burnt to produce X cal heat is(CH4+2O2 →CO2+2H2O, ΔH= –200K.Cal)

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Detailed Solution

q =m CpΔT = 3.6 cal16gm -------200Kcal? -------3.6 x 10-3 Kcal = 288 x 10-6gm= 0.288 mg

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