Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

Heat capacity of water is 18 cal-degree-1-mol-1. The quantity of heat needed to rise temperature of 18g water by 0.2oC is X cal. Then amount of CH4(g) to be burnt to produce X cal heat is(CH4+2O2 →CO2+2H2O, ΔH= –200K.Cal)

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

answer is 4.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

q =m CpΔT     = 3.6 cal16gm -------200Kcal?      -------3.6 x 10-3 Kcal    = 288 x 10-6gm= 0.288 mg
Watch 3-min video & get full concept clarity

courses

No courses found

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon