Q.

Heat of combustion of benzoic acid  at constant volume and 298 K is –3233kJ/mole. When 0.5g of benzoic acid is burnt in bomb calorimeter, the temperature of calorimeter increased by 0.530c. Now in the same bomb calorimeter when 1g of ethane is burnt then temperature increased by 2.040c. ΔH for combustion of ethane is

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answer is 2.

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Detailed Solution

Q = heat capacity of the calorimeterΔt = rise in temperatureM = Molar mass of substancem = mass of substance taken  Since bomb calorimeter is same, Q is same     ΔH= ΔU + ΔnRT     = -1530 + (-5/2) x 8.314 x 10-3 x 298     = -1536.2KJ/mole
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