A heat engine operating between 227°C and 77°C absorbs 10 kcal of heat from the 227°C reservoir reversibly per cycle. The total work done (in kcal) in two cycles.

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answer is 6.

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Detailed Solution

η=T2−T1T2=−wTotal q2⇒500−350500=−wTotal 10Work done in one cycle =3 Work done in two cycles = 3 × 2 = 6

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