The heat of formation of $$C2H5OHl$$ is $$-66$$ $$kcal/mol$$. The heat of combustion of $$CH3OCH3g$$ is $$-348$$ $$kcal/mol$$. ∆Hf for $$H2O$$ and $$CO2$$ are $$-68$$ $$kcal/mol$$ and $$-94$$ $$kcal/mol$$ respectively. Then, the ∆H for the isomerisatin reaction $$C2H5OHl$$ →$$CH3OCH3g$$, and ∆E for the same are at $$T=250C$$

Question

The heat of formation of $$C2H5OHl$$  is $$-66$$ $$kcal/mol$$. The heat of combustion of $$CH3OCH3g$$  is $$-348$$ $$kcal/mol$$. ∆Hf  for $$H2O$$ and $$CO2$$  are $$-68$$ $$kcal/mol$$ and $$-94$$ $$kcal/mol$$ respectively. Then, the ∆H for the isomerisatin reaction $$C2H5OHl$$ →$$CH3OCH3g$$,  and ∆E for the same are at $$T=250C$$

Infinity Learn · Accepted Answer

∆$$Hf0C2H5OHl$$  $$=$$ $$-66$$ $$kcal/mol$$ $$2C+3H2+12O2$$ →$$C2H5OH$$; ∆$$H=-66$$ $$kcal/mol$$                                        .....$$.1$$ $$CH3-O-CH3+3O2$$   →  $$2CO2+3H2O$$ ∆$$H=-348$$ $$kcal/mol$$                                     .....$$.2$$ $$H2g+O2g$$ →  $$H2O$$∆$$H3=-68$$ $$kcal/mol$$  ..$$.3$$ $$C+12O2$$   →   $$CO2$$ ∆$$H4=-9$$ $$kcal/mol$$                                              .....$$.4Target$$ equation $$=$$ $$-eq$$. $$1$$ $$-$$ eq. $$2$$ $$+$$ $$3$$ eq. $$3$$ $$+$$ $$2eq$$. $$2$$∆$$H=+66+348-3$$ × $$68-2$$×$$94=+66+348-204-188$$;  ∆$$H=22$$ $$kcal/mol$$ ∆$$H=$$∆$$E+$$∆ngRT⇒ $$22$$ $$=$$  ∆E $$+1$$ × $$2$$ × $$298$$ × $$10-3$$; ∆E $$=$$ $$21.4$$ $$kcal/mol$$

The heat of formation of C2H5OHl is -66 kcal/mol. The heat of combustion of CH3OCH3g is -348 kcal/mol. ∆Hf for H2O and CO2 are -68 kcal/mol and -94 kcal/mol respectively. Then, the ∆H for the isomerisatin reaction C2H5OHl →CH3OCH3g, and ∆E for the same are at T=250C

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