Q.
Heat of hydrogenation of ethene is x1 and that of benzene is x2. Hence resonance energy of benzene is
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a
x2−3x1
b
x1+x2
c
3x1−x2
d
x1−3x2
answer is C.
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Detailed Solution
and ΔrHobs=x2∴ RE=ΔrHcal−ΔrHobs=3x1−x2
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