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The heat of reaction (∆H) for the formation of NH3 according to the reaction N2+3H2⇌2NH3 at 27°C was found to be - 91.94 kJ. What will be the heat of reaction ∆H at 50°C. [r = 8.31 J / mol / K).

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answer is 93.087 KJ.

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Detailed Solution

ΔH2−ΔH1T2−T1=ΔCp (We know CP (diatomic gas) =72R,CP( polyatomic gas =4R)∴ΔH50∘C−ΔH27∘C(50+273)−(27+273)=2×4R−72R+3×72RΔH50∘C=91.94+23×(−6R)=−93.087kJ

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