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Henry thinks that a mole contains 6.023 × 1024 molecules. Hence the mass of Henry’s mole of Nitrogen is

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a

2.8g

b

28g

c

280g

d

0.28g

answer is C.

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Detailed Solution

According Henry, Avagadro's number =6.023 x 10246.023 x 1023 molecules of N2 weight 28g6.023 x 1023molecules of N2 weight 'X'g

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Henry thinks that a mole contains 6.023 × 1024 molecules. Hence the mass of Henry’s mole of Nitrogen is