Henry’s constant of Argon gas at 298K temperature is 40kbar. Calculate the weight of Argon dissolved in 1000 grams of water when packed at a pressure of 7.2 bar and 298 K .

Henry’s lawPA = KH×XAXA= nAnA+nsolventnA <<<   nsolvent∴ XA = nAnsolventPA = KH ×  ηAηsolvent7.2 bar=40 ×103×nArgon100018nArgon = 7.2720 = 0.01w40 = 0.01Weight of Argon gas dissolved in 1 kg of water = 0.4g