Questions
Henry’s constant (in kbar) for four gases and in water at 298 K is given below :
This table implies that :
detailed solution
Correct option is A
1) Solubility ∝1KHSo, V – has highest solubility2) It is not related to data of the table 3) (P)8=KH8×(x)8(P)8=0.5×103×55.555.5+100018=250bar4) FUV :(P)V=KHV×(x)V(P)V=2×10-5×103×55.555.5+100018=0.01barSimilar Questions
The Henry's law constant does not depend upon
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