Q.

HI was heated in a sealed tube at 4400C  till the equilibrium was reached. HI was found to be 22% decomposed. The equilibrium constant for the dissociation of HI is [2HI⇌H2+I2]

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a

0.282

b

0.0796

c

0.0199

d

1.99

answer is C.

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Detailed Solution

2HI     100⇌   H20+I20100-22        11      11  78                    11     11   KC=11×1178×78=17×17=149=0.0199
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