Q.
HI was heated in a sealed tube at 4400C till the equilibrium was reached. HI was found to be 22% decomposed. The equilibrium constant for the dissociation of HI is [2HI⇌H2+I2]
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a
0.282
b
0.0796
c
0.0199
d
1.99
answer is C.
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Detailed Solution
2HI 100⇌ H20+I20100-22 11 11 78 11 11 KC=11×1178×78=17×17=149=0.0199
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