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Q.

A high altitude balloon contains 6.81 g of helium in 1.16 x 104 L at - 23oC. Assuming ideal gas behavior, how many grams of helium would have to be added to increase the pressure to 4.0 x 10-3atm ?

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a

1.27

b

1.58

c

2.68

d

2.23

answer is D.

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Detailed Solution

Pi=nRTV=6.814×0.0821×2501.16×104 =3.012×10−3Pf=4×10−3ΔP↑=1×10−3 nHe-added =10−3×1.16×1040.0821×250wt=nHe×4=2.24gm
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