How many elements are possible for 1st period of periodic table if azimuthal quantum number can have integral values from 0, 1,2... (n + 1)?

n=1                              n=2l=0,1,2                         l=0,1,2,3s,p,d                               s,p,d,f1s21p6⏟Ist period 2s21d10…    According to question value of azimuthal quantum number is 0 to (n+1)Therefore, for n = 1, l = 0, 1, 2                    for n = 2 , l = 0, 1, 2, 3Now applying (n+l) rule we get subshellfilling order like this :1s,1p,2s,...After 1p, the second shell starts filling only the elements having electrons present in 1s and 1p will belong to 1st period.Total Number of such element possible is2× (capacity of 1s subshell)+6 (capacity of1p subshell)which is equal to '8' elements.