First slide

Faraday's Laws

Question

How many Faradays are required to reduce 0.25 g of Nb (V) to the metal? (Atomic weight : Nb = 93g)

Easy

A

2.7 x 10^-3
B

1.3 x 10^-2
C

2.7 x 10^-2
D

7.8 x 10^-3

Solution

$\begin{array}{l} 0 .25 = \frac{93}{5} \times \frac{Q}{F} \\ ∴ Q = 1 .3 \times 10^{- 2} \end{array}$

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