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Question

How many of the following compounds violate octet rule?
$(i) {BrF}_{5} (ii) {SF}_{6} (iii) {IF}_{7} (iv) {XeOF}_{4} (v) {CIF}_{3} (vi) {PCI}_{4}^{\oplus}$

Moderate

Solution

$i. {BrF}_{5} = 10 e^{-'} s$
$ii. {SF}_{6} = 12 e^{-'} s$
$iii. {IF}_{7} = 14 e^{-'} s$
Hence (i) to (v) violate octet rule.

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Unlock the full solution & master the concept.

How many of the following compounds violate octet rule?(i) BrF5 (ii) SF6 (iii) IF7 (iv) XeOF4 (v) CIF3 (vi) PCI4⊕

i. BrF5=10e−'s ii. SF6=12e−' s iii. IF7=14e−' s Hence (i) to (v) violate octet rule.

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How many of the following compounds violate octet rule?
$(i) {BrF}_{5} (ii) {SF}_{6} (iii) {IF}_{7} (iv) {XeOF}_{4} (v) {CIF}_{3} (vi) {PCI}_{4}^{\oplus}$

$i. {BrF}_{5} = 10 e^{-'} s$
$ii. {SF}_{6} = 12 e^{-'} s$
$iii. {IF}_{7} = 14 e^{-'} s$
Hence (i) to (v) violate octet rule.