Q.

How many grams of concentrated nitric acid solution should be used to prepare 250 mL of 2.0 M HNO3. The concentrated acid is 70% HNO3

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a

45.0 g conc. HNO3

b

90.0 g conc. HNO3

c

70.0 g conc. HNO3

d

54.0 g conc. HNO3

answer is A.

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Detailed Solution

∵ Molarity = Weight of HNO3 Molecular mass of HNO3× Volume of solution (in L∴ Weight of HNO3  = Molarity × Molecular mass × Volume (in L ) =2×63×14 g=31.5 g It is the weight of 100%HNO3 But the given acid is 70%HNO3∴ Its weight =31.5×10070 g=45 g
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