Q.

How many grams of concentrated nitric acid solution should be used to prepare 250 mL of 2.0 M HNO3. The concentrated acid is 70% HNO3

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

45.0 g conc. HNO3

b

90.0 g conc. HNO3

c

70.0 g conc. HNO3

d

54.0 g conc. HNO3

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

∵ Molarity = Weight of HNO3 Molecular mass of HNO3× Volume of solution (in L∴ Weight of HNO3  = Molarity × Molecular mass × Volume (in L ) =2×63×14 g=31.5 g It is the weight of 100%HNO3 But the given acid is 70%HNO3∴ Its weight =31.5×10070 g=45 g
Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Books for IIT JEE
Best Books for NEET
How to Join IIT after 10th
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Books for IIT JEE
Best Books for NEET
How to Join IIT after 10th
whats app icon
How many grams of concentrated nitric acid solution should be used to prepare 250 mL of 2.0 M HNO3. The concentrated acid is 70% HNO3