Q.
How many grams of concentrated nitric acid solution should be used to prepare 250 mL of 2.0 M HNO3. The concentrated acid is 70% HNO3
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a
45.0 g conc. HNO3
b
90.0 g conc. HNO3
c
70.0 g conc. HNO3
d
54.0 g conc. HNO3
answer is A.
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Detailed Solution
∵ Molarity = Weight of HNO3 Molecular mass of HNO3× Volume of solution (in L∴ Weight of HNO3 = Molarity × Molecular mass × Volume (in L ) =2×63×14 g=31.5 g It is the weight of 100%HNO3 But the given acid is 70%HNO3∴ Its weight =31.5×10070 g=45 g
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