How many grams of NaHSO3 will be required to react with one litre of NaIO3 solution containing 5.8g of  NaIO3 according to the reaction ?IO3−  +  3HSO3− →   I− + 3H++3SO42−

Meq.  of  NaHSO3 = Meq.  of  NaIO3N  ×  V=5.8198 ×  6  ×  1000 since n−factor  for  NaIO3=6             =175.76WNaHSO3MNaHSO3×  2  ×  1000 =175.76∴   WNaHSO3  =  175.76 ×  1042000 = 9.14  g