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Q.

How many grams of phosphoric acid would be needed to neutralise 100 g of magnesium hydroxide? (The molecular weights are: H3PO4 = 98 and Mg(OH)2= 58.3)

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a

66.7 g

b

252 g

c

112 g

d

168 g

answer is C.

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Detailed Solution

3Mg(OH)2+2H3PO4⟶Mg3PO42+3H2O3×58.32×98=100W,∴W=112g
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How many grams of phosphoric acid would be needed to neutralise 100 g of magnesium hydroxide? (The molecular weights are: H3PO4 = 98 and Mg(OH)2= 58.3)