How many milliliters of 0.05M K4Fe(CN)6 solution are required for titration of 60 ml of 0.01 M ZnSO4 solution, when the product of reaction is K2Zn3FeCN62?

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answer is 8.

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Detailed Solution

4k4FeCN6+6ZnSo4→2K2Zn3FeCN62+6K2So4mimak4FeCN6=mimaznSo44→6x×0.05→60×0.1x=4×60×0.10.05×6=8

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