How many minimum number of moles of KMnO4 should be decomposed to get sufficient oxygen for the complete combustion of 4.48L of C3H8 at STP?

C3H8+5O2→3CO2+4H2O22.4LC3H8 at STP require 5 moles O25.6LC3H8 at STP require 1 moles O22KMnO4→K2MnO4+MnO2+O2For 1 mole O2 minimum 2 moles KMnO4 required