Q.
How many molecule are present in 12 L of liquid CCl4 ? The density of the liquid is 1.59 g cm−3 ?
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answer is 1.
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Detailed Solution
1 cc of CCl4 contains 1.59 g of it∴ 12 L of liquid CCl4 will contain = 12 × 1000 ×1.59=159×120molecular wt. of CCl4=12+4(35.5)=154gnumber of molecules=n×6.023×1023=159×120154×6.023×1023 =0.744×1026
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