How many moles of ferric alum (NH4)2SO4Fe2(SO4)3.24H2O can be made from the sample of Fe containing 0.0056 g ofit?

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10-4 mol

0.5 x 10-4 mol

0.33 x 10-4 mol

2 x 10-4 mol

answer is B.

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Detailed Solution

Moles of Fe = 0.005656=10-4mol1 mol of alum = 2 mol of Fe2 mol of Fe = 1 mol of alum10-4mol of Fe = 12×10-4mol=0.5×10-4mol

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