How many moles of P4 can be produced by reaction of 0.10 moles Ca5(PO4)3F,0.36 moles SiO2, and 0.90 moles C according to the following reaction ?4Ca5PO43F+18SiO2+30C⟶3P4+2CaF2+18CaSiO3+30CO

4Ca5PO43F+18SiO20.36L⋅R+30C0.9⟶3P4+2CaF2+18CaSiO3+30COSiO2 is the Limiting reagent (∵0.36 moles of SiO2 requires 0.6moles of Carbon)18 mole SiO2 gives 3 mole P40.36 mole SiO2 will give =318×0.36=0.06 mole