How many moles of P4 can be produced by reaction of 0.10 moles Ca5 (PO4)3 F, 0.36 moles SiO2 and 0.90 moles C according to the following reaction ?4Ca5PO43F+18SiO2+30C⟶3P4+2CaF2+18CaSiO3+30CO

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0.060

0.030

0.045

0.075

answer is A.

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Detailed Solution

4Ca5PO43F+18SiO2+30C⟶3P4+2CaF2+18CaSiO3+30CO0.1 0.36 0.9 Limiting reagent is SiO218 moles of SiO2 gives = 3 moles of P40.36 mole of SiO2 gives = 318×0.36=0.06 mole

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