How many number of molecules and atoms respectively are present in 2.8 L of a diatomic gas at STP?

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6.023×1023,7.5×1023

6.023×1023,15×1022

7.5×1022,15×1022

15×1022,7.5×1023

answer is C.

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Detailed Solution

Number of molecules of gas at STP = 6.023×1023×2.822.4 =7.5×1022 molecules Number of atoms in diatomic molecule = 2×7.5×1022 =15×1022 atoms

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