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Q.

How many number of moles of  AgCl is precipitated, when1 mole of CoNH35ClCl2 Complex is treated with excess AgNO3 ?

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a

3

b

1

c

2

d

4

answer is C.

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Detailed Solution

CoNH35ClCl2 +AgNO3(excess)      →CoNH35Cl(NO3)2  +2AgCpptl↓, 1 mole of given complex treated with excess AgNO3 to form 2 moles of AgCl precipitate is formed
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