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Q.

How many unit cells are present in a cube shaped lattice crystal of NaCl of mass 1.00 g?[Atomic mass : Na = 23, Cl = 35.5]

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a

2.57 x 1021

b

5.14 x 1021

c

1.28 x 1021

d

1.71 x 1021

answer is A.

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Detailed Solution

Mass of one unit cell (m) = volume x density                                     =a3×d=a3×MZNAa3A=MZNA m=58.5×46.02×1023g∴Number of unit cells in 1g=1m=6.02×102358.5×4=2.57×1021
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