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How much amount  of AgCl is precipitated, when 1 mole of CoNH36Cl3 Complex is treated with excess AgNO3 ?

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By Expert Faculty of Sri Chaitanya
a
143.5 gr
b
287 gr
c
430.5 gr
d
574 gr

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detailed solution

Correct option is B

CoNH35ClCl2+AgNO3(excess)      →CoNH35Cl(NO3)2  +2AgCpptl↓,1 mole of given complex treated with excess AgNO3 to form 2 moles of AgCl precipitate is formed, that is 2x 143.5=287 gr AgCl ppt out.


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