First slide

Werner's theory

Question

How much amount of AgCl is precipitated, when 1 mole of $[Cr {(H_{2} O)}_{6}] {Cl}_{3}$ Complex is treated with excess AgNO₃ ?

Moderate

A

143.5 gr
B

287 gr
C

430.5 gr
D

574 gr

Solution

$[Cr {(H_{2} O)}_{6}] {Cl}_{3} + \underset{}{{AgNO}_{3} (excess) \to {[Cr {(H_{2} O)}_{6}] ({NO}_{3})}_{3}} + 3 AgCl ↓$ ,1 mole of given complex treated with excess AgNO₃ to form 1 mole of AgCl precipitate is formed, that is 430.5 gr AgCl ppt out.

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