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Q.

How much amount  of AgCl is precipitated, when 1 mole of Pt(en)H2OCl3Cl Complex is treated with excess AgNO3 ?

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a

143.5 gr

b

287 gr

c

430.5 gr

d

574 gr

answer is A.

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Detailed Solution

Pt(en)H2OCl3Cl+AgNO3(excess)      →Pt(en)H2OCl3(NO3)  +1AgCpptl↓,1 mole of given complex treated with excess AgNO3 to form 1 mole of AgCl precipitate is formed, that is 143.5 gr AgCl ppt out.
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