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Q.

How much amount of AgCl is precipitated, when 1 mole of Pt(en)2(H2O)ClCl3 Complex is treated with excess AgNO3 ?

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a

143.5 gr

b

287 gr

c

430.5 gr

d

574 gr

answer is C.

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Detailed Solution

Pt(en)2(H2O)ClCl3+AgNO3(excess) →Pt(en)2(H2O)Cl(NO3)3 +3AgCpptl↓,1 mole of given complex treated with excess AgNO3 to form 3 moles of AgCl precipitate is formed, that is 430.5 gr AgCl ppt out.

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