How much PCl5 must be added to a one litre vessel kept at 2500C in order to obtain 0.1 mole of Cl2 gas. KC for PCl5g⇌PCl3g+Cl2gis 0.0414 mol/L

GivenMoles of Cl2(g) at equilibrium = 0.1Volume of the vessel = 1 litreDue to the decomposition of PCl5 equal moles of PCl3 and Cl2 are formed moles of PCl3(g) at equilibrium = 0.1NowPCl3(g) +Number of moles of PCl5 = 0.341