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Question

How much propanol is required for dehydration to obtain 2.24 litres of propene at S.T.P is ____ grams

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Solution

${CH}_{3} {CH}_{2} {CH}_{2} OH \to_{}^{conc H_{2} {SO}_{4}} {CH}_{3} CH = {CH}_{2} + H_{2} O$
60 grams ------------------------- 22.4 L of propene
? ------------------------- 2.24 L
6 grams

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