How much propanol is required for dehydration to obtain  2.24 litres of propene at S.T.P is ____ grams

${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2\mathrm{OH}\underset{ }{\overset{\mathrm{conc}{\mathrm{H}}_2{\mathrm{SO}}_4}{\to }}{\mathrm{CH}}_3\mathrm{CH}={\mathrm{CH}}_2+{\mathrm{H}}_2\mathrm{O}$

60  grams            -------------------------  22.4 L of propene

?                    -------------------------  2.24 L

6 grams