Hybridization of central atom in XeF2 molecule is------ and the shape of XeF2 molecule is ------
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
sp2, trigonal planar
b
sp3, angular
c
sp3d, linear
d
sp3d2, angular
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Number of electron pairs(EP)=V+M-C+A2; V=Group number of central atom; M=-H, -X, -OH....monovalent groups attached to central atom ; C=Charge of cation ; A=Charge of anion ; V=5,6,7,8 respectively for 15th, 16th, 17th, 18th group elements ; Number bond pairs, BP(according to VSEPR theory)=Number of atoms directly attached to central atom; =5,4,3,2 respectively in PCl5, SF4, ClF3, XeF2 ; Number lone pairs on central atom(LP)=EP-BP ; =0,1,2,3 respectively in PCl5, SF4, ClF3, XeF2; XeF2-'2' bp +'3' lp ; sp3d-Linear ;