First slide

Interhalogen compounds

Question

The hybridization in ICl₇ (AX₇) is

Easy

A

sp³d³
B

Sp³
C

sp³d
D

sp³d²

Solution

Third excited state $\large ns^1$ $\large np_x^1$ $\large np_y^1$ $\large np_z^1$ $\large nd_x_y^1$ $\large nd_x_z^1$ $\large nd_y_z^1$ one s-orbital, three p-orbitals and three d- orbitals intermix to produce 7 $\large sp^3d^3$ hybridisation

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