The hybridization of N in NO2+,NO3− and NH4+ respectively are:
sp,sp2,sp3
sp,sp3,sp2
sp2,sp,sp3
sp3,sp2,sp
1)NO2+
H=12[V+M−charge]
H=12[5+0−(+1)]
H=2(sp)
2) NO3-
H=12[5+0−(−1)]
H=3sp2
3) NH4+
H=12[5+4−(+1)]
H=4sp3