Q.

The hydrated salt Na2SO4.nH2O undergoes 55.9% loss in weight on heating and becomes anhydrous. The value of n will be

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a

5

b

7

c

3

d

10

answer is D.

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Detailed Solution

Loss in weight is due to nH2O∴142+18ng of Na2SO4.nH2O=18ng loss in weight of H2O100 g of Na2SO4.nH2O=18n×100142+18n∴18n×100142+18n=55.9Solve for n⇒n=9.99≈10
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The hydrated salt Na2SO4.nH2O undergoes 55.9% loss in weight on heating and becomes anhydrous. The value of n will be