A hydrocarbon AC4H8 on reaction with HCI gives a compound BC4H9Cl which on reaction with 1 mole of NH3 gives a compound CC4H11 N. On reacting with NaNO2 and HCI followed by treatment with water, compound 'C yields an optically active alcohol, D. Ozonolysis of A gives 2 moles of acetaldehyde.The structure of compound C is
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a
2-aminobutane
b
N,N-dimethylethanamine
c
diethylamine
d
butylamine
answer is A.
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Detailed Solution
On ozonolysis A gives 2 moles of acetaldehyde, so A isCH3CH=CHCH3The reactions are as follows