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Enthalpy of Combustion

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Question

A hydrocarbon contains 81.8% by weight of carbon. Empirical formula of the hydrocarbon is

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Solution

C H
Percentage by weight $81.8 g$ $18.2 g$
Number of g atoms $\frac{81 .8}{12} = 6 .82$ $\frac{18 .2}{1} = 18 .2$
Number of g atoms $\frac{6 .82}{6 .82} = 1$ $\frac{18 .2}{6 .82} = 2 .66$
Number of g atoms $1 \times 3 = 3$ $2.66 \times 3 = 8$

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	C	H
Percentage by weight	$81.8 g$	$18.2 g$
Number of g atoms	$\frac{81 .8}{12} = 6 .82$	$\frac{18 .2}{1} = 18 .2$
Number of g atoms	$\frac{6 .82}{6 .82} = 1$	$\frac{18 .2}{6 .82} = 2 .66$
Number of g atoms	$1 \times 3 = 3$	$2.66 \times 3 = 8$